Math Through Answer

$
\begin{align*}
2x^2 + 3(x-1)(x-2) & = 2x^2 + 3(x^2-3x+2)\\
&= 2x^2 + 3x^2 - 9x + 6\\
&= 5x^2 - 9x + 6
\end{align*}
$

\begin{document}
\begin{align*}
2x^2 + 3(x-1)(x-2) & = 2x^2 + 3(x^2-3x+2)\\
&= 2x^2 + 3x^2 - 9x + 6\\
&= 5x^2 - 9x + 6
\end{align*}
\end{document}

$
\begin{align*}
2x^2 + 3(x-1)(x-2) & = 2x^2 + 3(x^2-3x+2)\\
&= 2x^2 + 3x^2 - 9x + 6\\
&= 5x^2 - 9x + 6
\end{align*}
$

$\int_{0}^{1}\frac{x^{4}\left(1-x\right)^{4}}{1+x^{2}}dx=\frac{22}{7}-\pi$
${ x + a = a + x = x}$

$$
\frac{x^n-1}{x-1} = \sum_{k=0}^{n-1}x^k
$$

$$
\frac{a/b-c/d}{e/f-g/h}
$$

$\frac{1}{2}$
$\frac{2}{x+2}$

\documentclass{article}
\begin{document}
%You won't see this in the final document.
You do see this.
\end{document}

Evaluate the sum $\displaystyle\sum\limits_{i=0}^n i^3$.

$
2x^2 + 3(x-1)(x-2) & = 2x^2 + 3(x^2-3x+2)\\
&= 2x^2 + 3x^2 - 9x + 6\\
&= 5x^2 - 9x + 6
$


$\frac {x^2+5}{3x +1}$

$$
\sum_{k=0}^\infty\frac{(-1)^k}{k+1} = \int_0^1\frac{dx}{1+x}
$$

$$
50 apples \times 100 apples = lots of apples
$$

\begin{eqnarray*}
1+2+\ldots+n&=&\frac{1}{2}((1+2+\ldots+n)+(n+\ldots+2+1))\\
&=&\frac{1}{2}\underbrace{(n+1)+(n+1)+\ldots+(n+1)}_{\mbox{$n$copies}}\\
&=&\frac{n(n+1)}{2}\\
\end{eqnarray*}

\begin{document}
\begin{align*}
2x^2 + 3(x-1)(x-2) & = 2x^2 + 3(x^2-3x+2)\\
&= 2x^2 + 3x^2 - 9x + 6\\
&= 5x^2 - 9x + 6
\end{align*}
\end{document}

$
\begin{align*}
2x^2 + 3(x-1)(x-2) & = 2x^2 + 3(x^2-3x+2)\\
&= 2x^2 + 3x^2 - 9x + 6\\
&= 5x^2 - 9x + 6
\end{align*}
$

----------------

$\begin{align*}
2x^2 + 3(x-1)(x-2) & = 2x^2 + 3(x^2-3x+2)\\
&= 2x^2 + 3x^2 - 9x + 6\\
&= 5x^2 - 9x + 6
\end{align*}$

$a$
$f(x) = 3x + 7$
f(x) = 3x + 7
Let $f$ be the function defined by $f(x) = 3x + 7$, and
let $a$ be a positive real number.
http://www.maths.tcd.ie/~dwilkins/LaTeXPrimer/MathMode.html

$a/b$
$\sqrt[3]{x+y}$
\frac{num}{den}
$\frac{1}{2}$
$a + b= c$
$\frac{w+a}{d+3}=\frac{r}{t}$
$\cos^2 x +\sin^2 x = 1$
\[\LaTeX\]
\frac{1}{2}

The solution to \[\sqrt{x} = 5\] is \[x=25.\]

The solution to
\[\sqrt{x} = 5\]
is
\[x=25.\]

$frac{x+y}{y-z)$

http://www.forkosh.dreamhost.com/source_mathtex.html
http://www.public.asu.edu/~rjansen/latexdoc/ltx-2.html
http://texblog.net/latex-archive/maths/eqnarray-align-environment/
http://andy-roberts.net/misc/latex/latextutorial10.html
http://andy-roberts.net/misc/latex/latextutorial9.html

nie jawapan saya

$a/b$

becomes

$a/b$

This is some introduction text. Bla bla

Click me to read spoilers

[spoiler][math]\int_a^bf(x)\,dx[/math] Oh dear![/spoiler]

[spoiler]$\int_a^bf(x)\,dx$ Oh dear![/spoiler]

Solution

[spoiler][math]\int_a^bf(x)\,dx[/math] Oh dear![/spoiler]

[spoiler]$\int_a^bf(x)\,dx$ Oh dear![/spoiler]

[spoiler]$\int_a^bf(x)\,dx $ Oh dear![/spoiler]

$Latex$

$TheSolutionof$

The solution to \[\sqrt{x} = 5\] is \[x=25.\]

Evaluate the sum $\displaystyle\sum_{i=0}^n i^3$.

2x^2 + 3(x-1)(x-2)&=&2x^2 + 3(x^2-3x+2)\\
&=& 2x^2 + 3x^2 - 9x + 6\\
&=& 5x^2 - 9x + 6

\documentclass{article}
\begin{document}
\begin{eqnarray*}
2x^2 + 3(x-1)(x-2)&=&2x^2 + 3(x^2-3x+2)\\
&=& 2x^2 + 3x^2 - 9x + 6\\
&=& 5x^2 - 9x + 6
\end{eqnarray*}
\end{document}

$\mathbf{\left(x-1\right)\left(x+3\right) }$

$$
\int_0^{2\pi}\cos(mx)\,dx = 0 \hspace{1cm}
\mbox{if and only if} \hspace{1cm} m\ne 0
$$
http://frodo.elon.edu/tutorial/tutorial/node25.html

\text {The solution to}\: \sqrt{x} = 5 \: \: \text {is} \: \: \, x = 25

$\text {The solution to}\: \sqrt{x} = 5 \: \: \text {is} \: \: \, x = 25$
http://www.mathhelpforum.com/math-help/latex-help/126399-how-make-sentence-spacing.html

$\[ \cos(\theta + \phi) = \cos \theta \cos \phi
- \sin \theta \sin \phi \]$
http://www.maths.tcd.ie/~dwilkins/LaTeXPrimer/StdFuncts.html

[math]

1+1 = 4/2
[/math]

$\(a + b = c\)$

$(a + b = c)$

\int_{0}^{1}\frac{x^{4}\left(1-x\right)^{4}}{1+x^{2}}dx=\frac{22}{7}-\pi

$\int_{0}^{1}\frac{x^{4}\left(1-x\right)^{4}}{1+x^{2}}dx=\frac{22}{7}-\pi$

$\frac{1}{2}mv^2$

$\(A = \pi r^{2}\)$

$(a) \(A = \pi r^{2}\)$

$(a)\(A = \pi r^{2}\)$

a) $\(A = \pi r^{2}\)$

$\color{blue}95800^4 + 217519^4 + 414560^4 = 422481^4$

The solution to $\sqrt{x} = 5$ is $x=25$.

$The solution to$ $\sqrt{x} = 5$ is $x=25$.

$The solution to $\sqrt{x} = 5$ is $x=25$.

$The solution to \sqrt{x} = 5 is x=25$.

Ref: http://www.artofproblemsolving.com/LaTeX/AoPS_L_BasicMath.php

\documentclass{article}
\begin{document}
The solution to $\sqrt{x} = 5$ is $x=25$.
\end{document}

$(a) sqrt{25}=5$

(a) $sqrt{25}=5$

\sqrt[root]{25}

$\sqrt[3]{x+y}$ ----http://www.personal.ceu.hu/tex/math.htm

$\sqrt[root]{25}$

$\sqrt[2]{25}$

$\sqrt[]{25}$

$\sqrt[]{25}=5$


http://www.andy-roberts.net/misc/latex/latextutorial9.html

\frac{x+y}{y-z}
$\frac{x+y}{y-z}$
$frac{x+y}{y-z}$
$$(\frac{x^2}{y^3})$$

[ math] ...... [ /math]
[ math] 2+1 [ /math]
$2+1$
[math]
1+1 = 4/2
[/math]

Sebelum dapat latex image seperti yang dikehendaki i.e $y=1-x^2$ berikut adalah cth2 kesalahan yang dilakukan

(a)\y=1-x^2\

(b) lupa

hasil daripada rujukan @

Ref: http://watchmath.com/vlog/?p=1244
Section of Ref : Usage
Quote Section :


baru jumpa 'key. dia camamner nak buat..patutla

@ http://mymaths.blogspot.com/2008/07/using-latex-in-blogger.html

watchmath said...

Hi, I have another solution to write latex on Blogger. It is based on mathtex.
It can write latex symbol by just putting latex code inside two dollar signs.
Check out my article here: http://watchmath.com/vlog/?p=438
10 July 2009 20:32